AUTHORIZED C_ABAPD_2309 TEST DUMPS | LATEST C_ABAPD_2309 TEST SAMPLE

Authorized C_ABAPD_2309 Test Dumps | Latest C_ABAPD_2309 Test Sample

Authorized C_ABAPD_2309 Test Dumps | Latest C_ABAPD_2309 Test Sample

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SAP C_ABAPD_2309 Exam Syllabus Topics:

TopicDetails
Topic 1
  • ABAP core data services and data modeling: It focuses on Core Data Services (CDS) views, SAP HANA database tables, foreign key relationships, and annotations.
Topic 2
  • Core ABAP programming: This topic covers ABAP data types, the ABAP dictionary, modularization, exceptions, and logical expressions, operator precedence.
Topic 3
  • ABAP RESTful Application Programming Model: This topic explains the ABAP Restful Application Programming model, ABAP development, and the architecture of the ABAP Restful Application Programming model.
Topic 4
  • SAP clean core extensibility and ABAP cloud: The topic explains extension pattern, extension rules, ABAP cloud development, and ABAP cloud rules.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q80-Q85):

NEW QUESTION # 80

What are valid statements? Note: There are 3 correct answers to this question

  • A. Class CL1 implements the interface.
  • B. Class CL1 uses the interface.
  • C. Class CL2 uses the interface.
  • D. In class CL1, the interface method is named if-ml.
  • E. In class CL2, the interface method is named ifl-ml.

Answer: A,B,E

Explanation:
Explanation
The following are the explanations for each statement:
C: This statement is valid. Class CL1 uses the interface. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The INTERFACES statement makes the class compatible with the interface and inherits all the components of the interface. The class can then use the interface components, such as the method ml, by using the interface component selector ~, such as ifl~ml12 E: This statement is valid. Class CL1 implements the interface. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The INTERFACES statement makes the class compatible with the interface and inherits all the components of the interface. The class must then provide an implementation for the interface method ml in the implementation part of the class, unless the method is declared as optional or abstract12 D: This statement is valid. In class CL2, the interface method is named ifl~ml. This is because class CL2 has a data member named m0_ifl of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable m0_ifl. The interfacemethod ml has the name ifl~ml in the class, where ifl is the name of the interface and the character ~ is the interface component selector12 The other statements are not valid, as they have syntax errors or logical errors. These statements are:
A: This statement is not valid. In class CL1, the interface method is named ifl~ml, not if-ml. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The interface ifl defines a method ml, which can be called using the class name or a reference to the class. The interface method ml has the name ifl~ml in the class, where ifl is the name of the interface and the character ~ is the interface component selector. Using the character - instead of the character ~ will cause a syntax error12 B: This statement is not valid. Class CL2 does not use the interface, but only has a reference to the interface. This is because class CL2 has a data member named m0_ifl of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable m0_ifl. However, class CL2 does not implement the interface ifl, nor does it inherit the interface components. Therefore, class CL2 does not use the interface, but only references the interface12 References: INTERFACES - ABAP Keyword Documentation, CLASS - ABAP Keyword Documentation


NEW QUESTION # 81
Which of the following string functions are predicate functions? Note: There are 2 correct answers to this question.

  • A. find_any_not_of()
  • B. matchesQ
  • C. count_any_of()
  • D. contains_any_of()

Answer: B,D

Explanation:
String functions are expressions that can be used to manipulate character-like data in ABAP. String functions can be either predicate functions or non-predicate functions. Predicate functions are string functions that return a truth value (true or false) for a condition of the argument text. Non-predicate functions are string functions that return a character-like result for an operation on the argument text1.
The following string functions are predicate functions:
B) contains_any_of(): This function returns true if the argument text contains at least one of the characters specified in the character set. For example, the following expression returns true, because the text 'ABAP' contains at least one of the characters 'A', 'B', or 'C':
contains_any_of( val = 'ABAP' set = 'ABC' ).
D) matches(): This function returns true if the argument text matches the pattern specified in the regular expression. For example, the following expression returns true, because the text 'ABAP' matches the pattern that consists of four uppercase letters:
matches( val = 'ABAP' regex = '[A-Z]{4}' ).
The following string functions are not predicate functions, because they return a character-like result, not a truth value:
A) find_any_not_of(): This function returns the position of the first character in the argument text that is not contained in the character set. If no such character is found, the function returns 0. For example, the following expression returns 3, because the third character of the text 'ABAP' is not contained in the character set 'ABC':
find_any_not_of( val = 'ABAP' set = 'ABC' ).
C) count_any_of(): This function returns the number of characters in the argument text that are contained in the character set. For example, the following expression returns 2, because there are two characters in the text 'ABAP' that are contained in the character set 'ABC':
count_any_of( val = 'ABAP' set = 'ABC' ).


NEW QUESTION # 82
What are valid statements? Note: There are 3 correct answers to this question

  • A. Class CL2 uses the interface.
  • B. Class CL1 implements the interface.
  • C. In class CL1, the interface method is named if-ml.
  • D. Class CL1 uses the interface.
  • E. In class CL2, the interface method is named ifl-ml.

Answer: A,B,E

Explanation:
The following are the explanations for each statement:
* C: This statement is valid. Class CL1 uses the interface. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The INTERFACES statement makes the class compatible with the interface and inherits all the components of the interface. The class can then use the interface components, such as the method ml, by using the interface component selector ~, such as ifl~ml12
* E: This statement is valid. Class CL1 implements the interface. This is because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The INTERFACES statement makes the class compatible with the interface and inherits all the components of the interface. The class must then provide an implementation for the interface method ml in the implementation part of the class, unless the method is declared as optional or abstract12
* D: This statement is valid. In class CL2, the interface method is named ifl~ml. This is because class CL2 has a data member named m0_ifl of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable m0_ifl. The interface method ml has the name ifl~ml in the class, where ifl is the name of the interface and the character ~ is the interface component selector12 The other statements are not valid, as they have syntax errors or logical errors. These statements are:
* A: This statement is not valid. In class CL1, the interface method is named ifl~ml, not if-ml. This is
* because class CL1 implements the interface ifl using the INTERFACES statement in the public section of the class definition. The interface ifl defines a method ml, which can be called using the class name or a reference to the class. The interface method ml has the name ifl~ml in the class, where ifl is the name of the interface and the character ~ is the interface component selector. Using the character - instead of the character ~ will cause a syntax error12
* B: This statement is not valid. Class CL2 does not use the interface, but only has a reference to the interface. This is because class CL2 has a data member named m0_ifl of type REF TO ifl, which is a reference to the interface ifl. The interface ifl defines a method ml, which can be called using the reference variable m0_ifl. However, class CL2 does not implement the interface ifl, nor does it inherit the interface components. Therefore, class CL2 does not use the interface, but only references the interface12 References: INTERFACES - ABAP Keyword Documentation, CLASS - ABAP Keyword Documentation


NEW QUESTION # 83
Exhibit:

With Icl_super being superclass for Icl_subl and Icl_sub2 and with methods subl_methl and sub2_methl being subclass-specific methods of Id_subl or Icl_sub2, respectivel. What will happen when executing these casts?
Note:
There are 2 correct answers to this question

  • A. go sub2->sub2 meth 1(...). will work
  • B. go sub1 = CAST # go super), will not work
    go_sub2 = CAST # go super), will work.
  • C. go_sub1 CAST #go_super), will work
    go_sub2 = CAST #(go_super). will not work.
  • D. go_sub1->sub1_meth 1(...). will work.

Answer: C,D

Explanation:
The following are the explanations for each statement:
* A: This statement is correct. go_subl = CAST #(go_super) will not work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_subl, but this is not possible, as go_super is not pointing to an instance of cl_subl, but to an instance of cl_super. Therefore, the CAST operator will raise an exception CX_SY_MOVE_CAST_ERROR at runtime12
* B: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_subl = CAST #(go_super) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the CAST operator will not work for go_subl, as explained in statement A12
* C: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_sub2->sub2_meth1(...) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super. Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the method call go_sub2->sub2_meth1(...) will not work, as sub2_meth1 is a subclass-specific method of cl_sub2, which is not inherited by cl_super. Therefore, the method call will raise an exception CX_SY_DYN_CALL_ILLEGAL_METHOD at runtime123
* D: This statement is correct. go_subl->subl_meth1(...) will work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. subl_meth1 is a subclass- specific method of cl_subl, which is not inherited by cl_super. Therefore, the method call go_subl-
>subl_meth1(...) will work, as go_subl is pointing to an instance of cl_subl, which has the method subl_meth1123 References: NEW - ABAP Keyword Documentation, CAST - ABAP Keyword Documentation, Method Call
- ABAP Keyword Documentation


NEW QUESTION # 84
In a subclass subl you want to redefine a component of a superclass superl. How do you achieve this? Note:
There are 2 correct answers to this question.

  • A. You implement the redefined component for a second time in superl.
  • B. You add the clause REDEFINITION to the component in superl.
  • C. You implement the redefined component in subl.
  • D. You add the clause REDEFINITION to the component in subl.

Answer: C,D

Explanation:
To redefine a component of a superclass in a subclass, you need to do the following12:
* You add the clause REDEFINITION to the component declaration in the subclass. This indicates that the component is inherited from the superclass and needs to be reimplemented in the subclass. The redefinition must happen in the same visibility section as the component declaration in the superclass.
For example, if the superclass has a public method m1, the subclass must also declare the redefined method m1 as public with the REDEFINITION clause.
* You implement the redefined component in the subclass. This means that you provide the new logic or behavior for the component that is specific to the subclass. The redefined component in the subclass will override the original component in the superclass when the subclass object is used. For example, if the superclass has a method m1 that returns 'Hello', the subclass can redefine the method m1 to return
'Hi' instead.
You cannot do any of the following:
* You implement the redefined component for a second time in the superclass. This is not possible, because the superclass already has an implementation for the component that is inherited by the subclass. The subclass is responsible for providing the new implementation for the redefined component, not the superclass.
* You add the clause REDEFINITION to the component in the superclass. This is not necessary, because the superclass does not need to indicate that the component can be redefined by the subclass. The subclass is the one that needs to indicate that the component is redefined by adding the REDEFINITION clause to the component declaration in the subclass.
References: 1: METHODS - REDEFINITION - ABAP Keyword Documentation - SAP Online Help 2:
Redefining Methods - ABAP Keyword Documentation - SAP Online Help


NEW QUESTION # 85
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